SOLUTION: how can i find the value of y? 4^2y + 4^(2y-1) = 4

Question 657944: how can i find the value of y?
4^2y + 4^(2y-1) = 4
Found 3 solutions by Alan3354, Edwin McCravy, MathLover1:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
how can i find the value of y?
4^2y + 4^(2y-1) = 4
-----------------------

(2y-1)*log(4) = log(0.8)
2y-1 = log(0.8)/log(4)
y = (log(0.8)/log(4) + 1)/2

Answer by Edwin McCravy(20086)   (Show Source): You can put this solution on YOUR website!

+ = We use the principle that on the second term: + = We change the to + = Multiply through by 4 to remove the fraction: + = + = + = The two terms on the left are like terms and combine as = Then we divide both sides by 5 = Now we take logs of both sides = We use the principle = Divide both sides by = = 0.4195179763 Edwin

Answer by MathLover1(20855)   (Show Source): You can put this solution on YOUR website!

since we have
...both sides multiply by

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