# SOLUTION: Some "x-values" make the denominator of a rational function undefined. Why can't the graph of that function cross the vertical lines (vertical asymptotes) that have those values

Algebra ->  Algebra  -> College  -> Linear Algebra -> SOLUTION: Some "x-values" make the denominator of a rational function undefined. Why can't the graph of that function cross the vertical lines (vertical asymptotes) that have those values       Log On

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 Question 6569: Some "x-values" make the denominator of a rational function undefined. Why can't the graph of that function cross the vertical lines (vertical asymptotes) that have those values for "x-intercepts"?Answer by longjonsilver(2297)   (Show Source): You can put this solution on YOUR website!you answered your own question.... the x-values that make the function undefined are values that are UNDEFINED, so you cannot have that/those values, so you will never have the curve crossing the asymptote (--> the line denoting the undefined value) jon.