SOLUTION: S = n(a + l)/2 solve for l The first thing I did was use distributive property for n(a + l). So then: S = (na + nl)/2 Then, I thought about trying to cancel out the 2, lea

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Question 653117: S = n(a + l)/2 solve for l
The first thing I did was use distributive property for n(a + l). So then:
S = (na + nl)/2
Then, I thought about trying to cancel out the 2, leaving it as:
2S = 2na + 2nl
Am I on the right track?

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
That "l" looks too much like the number "1", so I'm going to 
use capital letters instead:

S = N(A + L)/2

Clear of fractions by multiplying both sides by 2

2S = 2N(A + L)/2

Then the 2's cancel on the right

2S = 2N(A + L)/2

and then we don't have any fractions:

2S = N(A + L)

Now remove the parentheses using the distributive principle:

2S = NA + NL

Now isolate the only term that contains L on the right by
subtracting NA from both sides:

2S - NA = NL

Finally we divide both sides by N which is the coefficient of L:

 = L

And if you like you can turn the equation around and write it as

L =  

Edwin

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