SOLUTION: I have done 7/10 of my homework. I will submit each one separately.
The answers are randomized on the back, but it seems as if they aren't correct.
#5. Alex is creating a rectan
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Question 643880: I have done 7/10 of my homework. I will submit each one separately.
The answers are randomized on the back, but it seems as if they aren't correct.
#5. Alex is creating a rectangular garden that has an area of 456 ft squared. If the length of the garden is 24 feet, what is the width of the garden?
I got 204 using 456= 2(24+w)
Answer by MathTherapy(10559) (Show Source): You can put this solution on YOUR website!
I have done 7/10 of my homework. I will submit each one separately.
The answers are randomized on the back, but it seems as if they aren't correct.
#5. Alex is creating a rectangular garden that has an area of 456 ft squared. If the length of the garden is 24 feet, what is the width of the garden?
I got 204 using 456= 2(24+w)
It appears from what you did that you're think PERIMETER instead of AREA. The question gives the AREA as 456 sq ft.
Let width be W
A = LW
456 = 24(W)
456 = 24W
W, or width = , or ft
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