# SOLUTION: fix it fast plumbing charges \$25 for a house call and \$50 for each hour spent on the job. do it right plumbing charges \$35 for a house call and \$45 for each hour spent on the job.

Algebra ->  Algebra  -> College  -> Linear Algebra -> SOLUTION: fix it fast plumbing charges \$25 for a house call and \$50 for each hour spent on the job. do it right plumbing charges \$35 for a house call and \$45 for each hour spent on the job.       Log On

 Algebra: Linear Algebra (NOT Linear Equations) Solvers Lessons Answers archive Quiz In Depth

 Question 619971: fix it fast plumbing charges \$25 for a house call and \$50 for each hour spent on the job. do it right plumbing charges \$35 for a house call and \$45 for each hour spent on the job. how many hours must be spent on the job in order for the charges of the two plumbingcompanies to be equal? Answer by dragonwalker(72)   (Show Source): You can put this solution on YOUR website!let us call the number of hours on the job as 'h' For each company the cost of a job is the initial house call fee plus the hourly fee multiplied by the number of hours on the job. For Fif the cost of a job can be written as 25 + 50h For DiR the cost of a job can be written as 35 + 45h For each fee to be equal we can write it as follows: 25 + 50h = 35 + 45h rearrange, remembering to change the sign if the value moves to the other side of the equation: 50h - 45h = 35 - 25 5h = 10 solve for h by dividing both sides by 5: 5h/5 = 10/5 h=2 so the number of hours on a job for the cost to be the same is 2 hours. To check we can substitute the value of h into the equations for each company and see if they are the same: For Fif the cost of a job can be written as 25 + 50h = 25 + 2(50) = 125!!! For DiR the cost of a job can be written as 35 + 45h = 35 + 2(45) = 125!!!