SOLUTION: how do I rewrite the quadratic equation y=x^2+6x-8 in vertex form

Algebra.Com
Question 611367: how do I rewrite the quadratic equation y=x^2+6x-8 in vertex form
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!



Now, complete the square on the right and then collect terms to result in a function that has the following pattern:



which is a parabola with a vertical axis of symmetry and a vertex of (h,k). The parabola opens upward if , downward otherwise. is the distance from the vertex to the focus of the parabola and is the distance from the vertex to the directrix.

John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism



RELATED QUESTIONS

how do I rewrite the quadratic equation x^2+6x-8 in vertex... (answered by solver91311,stanbon)
How do you find the vertex of this quadratic equation?... (answered by josmiceli)
How do you rewrite the equation y=x^2+6x+4 in vertex form by using the concept of... (answered by edjones)
Write the quadratic equation in vertex form. What is the vertex?... (answered by checkley79)
how do i rewrite the equation y=7x+8 in standard... (answered by nyc_function)
How would I write the equation in vertex form. How would I identify the vertex?... (answered by josgarithmetic)
Use completing the square to rewrite this equation in vertex form. x^2... (answered by ewatrrr)
vertex form y=-x^2+6x+4 i need in vertex form i cant find out how to do... (answered by fcabanski)
vertex form y=-x^2+6x+4 i need in vertex form i cant find out how to do... (answered by KMST)