SOLUTION: This is a two part question. Can anyone help me set these up. I seem to have issues with these slopes. Thanks! Using point P(2,9) and Q (-3,3) Find distance between P and

Question 60981: This is a two part question. Can anyone help me set these up. I seem to have issues with these slopes. Thanks!
Using point P(2,9) and Q (-3,3)
Find distance between P and Q.
Find the equation of the line passing through P and Q.
Thanks again!
Answer by joyofmath(189) (Show Source): You can put this solution on YOUR website!
The distance between two points if found by computing the hypotenuse of a right triangle using the Pythagorean Theorem .
In the case of P and Q, the length of one side of the triangle is found by calculating the distance between X values and the length of another side is found by calculating the distance between the Y values.
So, the y values are 2 and -3 and their difference is .
The y values are 9 and 3. Their difference .
Use the Pythagorean Theorem to find the shortest distance between these points, the hypotenuse of the triangle with sides 5 and 6.
. So, so which is approximately and that's the distance between the two points.
The formula for a line is where x is the slope and b is the y-axis intercept. The slope is the ratio of the change in x to the change in y.
We know from our work above that the x increases by 6 for every increase in 5 that the y goes up.
So, the slope is: .
So, the equation of the line is: .
We need to find x.
We can use the x and y values of either point to do that.
Using Q, (-3,3) we find that .
Or,
Or, .
So, .
Thus, the equation of the line is .
We verify this with both points:
If x = -3 and y = 3 then so .
If x = 2 and y = 9 then so .
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