SOLUTION: show that e^x and e^2x are independent.

Algebra.Com
Question 608556: show that e^x and e^2x are independent.
Found 2 solutions by ewatrrr, solver91311:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi, Note
A consistent system has at least one solution.
An inconsistent system has no solutions.
An independent system has exactly one solution.
A dependent system has infinitely many solutions.
show that e^x and e^2x are independent.(exactly one solution) (0,1)


Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Presuming you mean linearly independent, let be a vector space of all functions of a real variable .

Suppose and are two real numbers such that



If and are linearly independent then and

Divide by since is never zero



hence must be independent of which only occurs when . Therefore as well.

John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism


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