# SOLUTION: what is the equation of the line which passes through (2,3) and perpendicular to the line y=x-5

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 Click here to see ALL problems on Linear Algebra Question 578701: what is the equation of the line which passes through (2,3) and perpendicular to the line y=x-5 Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!Find the slope of this line 1 y = 1 x + 5 Divide by 1 y = 1 x + 5 Compare this equation with y=mx+b, m= slope & b= y intercept slope m = 1 The slope of a line perpendicular to the above line will be the negative reciprocal -1 m1*m2=-1 The slope of the required line will be -1 m= -1 ,point ( 2 , 3 ) Find b by plugging the values of m & the point in y=mx+b 3 = -2 + b b= 5 m= -1 The required equation is y = -1 x 5 m.ananth@hotmail.ca