SOLUTION: Perform the indicated operation 7. (4-2i)(8+4i) Simplify and write in a+bi form 10.i^38 Divide 13. 8+4i/7+3i

Question 566202: Perform the indicated operation
7. (4-2i)(8+4i)
Simplify and write in a+bi form
10.i^38
Divide
13. 8+4i/7+3i
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Perform the indicated operation
7. (4-2i)(8+4i)
Simplify and write in a+bi form
10.i^38
Divide
13. 8+4i/7+3i
**
i=√-1
i^2=-1
i^3=-i
i^4=1
..
(4-2i)(8+4i)=32-16i+16i-8i^2=32+8=40
..
i^38=i^36*i^2=-1
..
8+4i/7+3i
multiply top and bottom by conjugate of denominator
(8+4i)(7-3i)/(7+3i)(7-3i)
(56+4i-12i^2)/(7^2-9i^2)
(56+4i+12)/(49+9)
(68+4i)/58
68/58+4i/58=34/29+2i/29
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