SOLUTION: the line 3kx+6ky=7 isparallel to the line 9ky+8y=15. Find k

Question 478164: the line 3kx+6ky=7 isparallel to the line 9ky+8y=15. Find k
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
I think you have a TYPO in the second equation.
I believe you meant:
the line 3kx+6ky=7 is parallel to the line 9kx+8y=15. Find k
Put each into "slope-intercept" form:
y = mx + b
where
m is the slope
b is the y-intercept
.
3kx+6ky=7
6ky = -3kx+7
y = (-3kx+7)/(6k)
y = (-3k)/(6k)x + 7/(6k)
y = (-1/2)x + 7/(6k)
slope is -1/2
.
9kx+8y=15
8y = -9kx+15
y = (-9k)/8x+15/8
slope is -9k/8
.
if the two lines are parallel the slopes must be equal:
-1/2 = -9k/8
cross multiplying:
-8 = -18k
8/18 = k
4/9 = k

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