SOLUTION: Determine the horizontal asymptote of the grahp of B(t) = 1200 divided by 1+34e^-0.125t

Question 47515: Determine the horizontal asymptote of the grahp of B(t) = 1200 divided by 1+34e^-0.125t

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Determine the horizontal asymptote of the grahp of B(t) = 1200 divided by 1+34e^-0.125t

AS t goes to infinity, e^-0.125t goes to zero.
So B(t) = 1200/[1+34e^-0.125t] goes to 1200/1 = 1200
Cheers,
Stan H.
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