SOLUTION: x-y=2 (1)
3x-4z=15 (2)
3y+z=9 (3)
Is there a solution and if there is what are the solutions?
Algebra.Com
Question 473688: x-y=2 (1)
3x-4z=15 (2)
3y+z=9 (3)
Is there a solution and if there is what are the solutions?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x-y=2
3x-4z=15
3y+z=9
---------------
x - y + 0 = 2
3x + 0 -4z = 15
0 +3y + z = 9
-------------------------
Use any method you know to get:
x = 5
y = 3
z = 0
===============
Cheers,
Stan H.
==============
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