SOLUTION: Let the function "f" be defined by f(x)= x^2+18. If "m" is a positive number such that f(2m)= 2f(m), what is the value of m? The answer is 3, but I do not know how to get this a

SOLUTION: Let the function "f" be defined by f(x)= x^2+18. If "m" is a positive number such that f(2m)= 2f(m), what is the value of m? The answer is 3, but I do not know how to get this a

Algebra.Com

Question 464733: Let the function "f" be defined by f(x)= x^2+18. If "m" is a positive number such that f(2m)= 2f(m), what is the value of m?
The answer is 3, but I do not know how to get this answer. Can you help?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
2(m2+18)=(2m)2+18
2m2+36=4m2+18
2m2=18
m2=9
m=√9=3..
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