SOLUTION: Let U be a subspace of R^4 and let the set S={x1,x2,x3} be an orthogonal basis of U, where x1=[1,0,-1,-1] x2=[2,1,1,1] x3=[-1,3,-1,0]
a) find a basis of U^(orthogonal symbol)
Question 375894: Let U be a subspace of R^4 and let the set S={x1,x2,x3} be an orthogonal basis of U, where x1=[1,0,-1,-1] x2=[2,1,1,1] x3=[-1,3,-1,0]
a) find a basis of U^(orthogonal symbol)
b) Given x=[3,1,0,42] find vectors x1 and x2 such that x= x1+x2, where x1 is in U and x2 is in U^(orthogonal symbol) Answer by Jk22(389) (Show Source): You can put this solution on YOUR website! a) We take a vector which is orthogonal to : x1=[1,0,-1,-1] x2=[2,1,1,1] x3=[-1,3,-1,0]
let u[a,b,c,d], u.x1=u.x2=u.x3=0
since it's of dimension 1 (x1,x2,x3 are linearly independent), another way would be to calculate the cross product of x1,x2,x3 :
[e1 1 2 -1]
[e2 0 1 3]
[e3 -1 1 -1]
[e4 -1 1 0]
=e1
[0 1 3]
[-1 1 -1]
[-1 1 0]
=[1,-3,-10,11]=u1=-u
b) Given x=[3,1,0,42] find vectors x1 and x2 such that x= x1+x2, where x1 is in U and x2 is in U^(orthogonal symbol)
we project x on u1 :
fact=x.u1/|u1|^2=(3-3+42*11)/Sqrt(1+9+100+121)=462/231=2
x2=fact*u1=[1,-3,-10,11]*2=[2,-6,-20,22]
x1=x-x2=[3,1,0,42]-[2,-6,-20,22]=[1,7,20,20]