SOLUTION: the difference of the squares of two consecutive odd integers is 48. find the integers.

Algebra.Com
Question 36945: the difference of the squares of two consecutive odd integers is 48. find the integers.

Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
(X+2)~2-X~2=48 OR (X~2+4X+4)-X~2=48 OR X~2+4X+4-X~2=48 OR 4X-44 OR X=11 AND X+2=13
PROOF 13~22-11~2=48 OR 169-121=48 OR 48=48

RELATED QUESTIONS

the difference of the squares of two consecutive odd integers is 48. find the... (answered by checkley71)
the difference of the squares of two consecutive odd integers is 48. find the... (answered by checkley71)
find two consecutive positive odd integers such that the difference of their squares is... (answered by Alan3354)
The difference of the squares of two consecutive odd integers is 24. Find the integers. (answered by josgarithmetic)
find two consecutive odd integers such that the difference of their squares is... (answered by rapaljer)
Find two consecutive positive and odd integers such that the difference of their squares... (answered by Alan3354,Gersid)
Find two consecutive odd integers such that the difference of their squares is... (answered by mananth)
The sum of the squares of two consecutive odd integers is 34. Find the two... (answered by checkley71)
The sum of the squares of two consecutive odd integers is 34. Find the two... (answered by Earlsdon,checkley71)