SOLUTION: if the product of two consecutive odd integers is decreased by one third the lessre the integer, the result is 250. find the integers.

Question 36820: if the product of two consecutive odd integers is decreased by one third the lessre the integer, the result is 250. find the integers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
if the product of two consecutive odd integers is decreased by one third the lessre the integer, the result is 250. find the integers.
Let the lesser integer be "x"
Then the larger interger is "x+2"
EQUATION:
x(x+2)-(1/3)x=250
x^2+(5/3)x-250=0
3x^2+5x-750=0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=9025 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 15, -16.6666666666667. Here's your graph:

Hope this helps.
Cheers,
Stan H.
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