SOLUTION: k3' = k3k5/ k4+k5 k1' = k1A(k3'/k3'+k2) Unsure how to substitute k3' into second equation and simplify. Please help, step by step explaination is better. Thanks

Question 329671: k3' = k3k5/ k4+k5
k1' = k1A(k3'/k3'+k2)
Unsure how to substitute k3' into second equation and simplify. Please help, step by step explaination is better.
Thanks
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
I hope it's OK that I change some of your variables.
B=k3
C=k3'
D=k4
E=k5
F=k1
G=k1'
H=k2
k3' = k3k5/ k4+k5
1.
k1' = k1A(k3'/k3'+k2)
2.
Substitute eq. 1 into eq. 2,

Multiply numerator and denominator by

.
.
.
k1'=(k1*A*k3*k5)/(k3*k5+k4*k2+k5*k2)

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