SOLUTION: Solve the following system of nonlinear equations
y=x^4-x^2+2x-1
y=x^4+3x^2+2x-2
Algebra.Com
Question 328160: Solve the following system of nonlinear equations
y=x^4-x^2+2x-1
y=x^4+3x^2+2x-2
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve the following system of nonlinear equations
y = x^4 - x^2 + 2x - 1
y = x^4 +3x^2 + 2x - 2
Therefore
x^4 +3x^2 + 2x - 2 = x^4 - x^2 + 2x - 1
Combine like terms
x^4 - x^4 + 3x^2 + x^2 + 2x - 2x = -1 + 2
:
4x^2 = 1
x^2 =
x = +/-
x = +/-, or +/-.5
:
Find y using the 1st equation, x=+.5
y = .5^4 - .5^2 + 2(.5) - 1
y = .0625 - .25 + 1 - 1
y = -.1875
One solution: x=.5, y=-.1875
:
Find y using the 1st equation, x=-.5
y = -.5^4 - (-.5^2) + 2(-.5) - 1
y = .0625 - .25 - 1 - 1
y = -2.1875
A 2nd solution: x=-.5, y = -2.1875
:
I'll let you check the solutions in the 2nd equation
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