SOLUTION: the height in feet of an object thrown upward is given by the equation h=80t-16t^2, where h is the height of the object after t seconds. after how many seconds does the object reac

Question 324353: the height in feet of an object thrown upward is given by the equation h=80t-16t^2, where h is the height of the object after t seconds. after how many seconds does the object reach it maximum height?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the height in feet of an object thrown upward is given by the equation
h(t) = 80t-16t^2, where h is the height of the object after t seconds. after how many seconds does the object reach it maximum height?
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Max occurs when x = -b/2a = -80/(2(-16)) = 5/2 = 2.5 seconds
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Cheers,
Stan H.
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