SOLUTION: Question: x^2+5x>24 Possible Answers: a. none of these b. -3<x<8 c. x<-3 or x>8 d. X<-8 or x>3

Question 30152: Question:
x^2+5x>24
Possible Answers:
a. none of these
b. -3 c. x<-3 or x>8
d. X<-8 or x>3
Answer by sdmmadam@yahoo.com(530) (Show Source): You can put this solution on YOUR website!
x^2+5x>24
That is x^2+5x-24 > 0
(x+8)(x-3) > 0
Since either positive multiplied by positive is positive OR
negative multiplied by negative is positive, there are two cases.
Case 1: Let (x+8) > 0 together with (x-3) > 0
This implies x > -8 together with x > 3
And since anything to the right of 3 is definitely to the right of (-8),
the verdict for this case is
x > 3
Case 2: Let (x+8) < 0 together with (x-3) < 0
This implies x < -8 together with x < 3
And since anything to the left of (-8) is definitely to the left of 3,
the verdict for this case is
x < -8
Therefore combining the results of both the cases we have
Answer: x< -8 and x > 3
Which is your choice (d)
Note: (factoring the quadratic expression: x^2+5x-24,
product =(-24) and sum is 5 and therefore the quantities are (+8) and (-5)
and therefore x^2+5x-24
= x^2+(8x-3x)-24
= (x^2+8x)-3x-24
=x(x+8)-3(x+8)
=xp-3p where p = (x+8)
=p(x-3)
=(x+8)(x-3)

RELATED QUESTIONS
Hi, solve for x 5x - 3 - 2x ____________ = 24 7 I have (33/7)x = 27, x =... (answered by MathLover1)

Solve : x- ( 3 / x ) = 2 a) 1 b) -1 or 3 c) 3 d) -1 e) none of... (answered by joyofmath)

Solve for x: (x + 1)^3/2 = 8 A. 3 B. 5 C. 21.63 D. 25 E. None of... (answered by nabla)

If x^2 + y^2 = 40 and xy = 12, then x + y = A. 7. B. 8. C. 7 or −7. D. 8 or... (answered by checkley77)

Question: Solve x^4-10x^2+9=0 Possible Answers: (a) +1, +3 (b) 1, 9 (c) +1, +9... (answered by checkley71)

|x + 3| < 5 Possible answers- A.) �8 < x < 2 B.) �2 < x < 8 C.) 3 < x < 5 D.) �3 (answered by MathLover1)

In the xy � coordinate plane, the distance between point B(8, x) and point A(�8, �x) is... (answered by josgarithmetic)

refer to the function f(x)=3x^3-11x^2+5x+3 Use DesCartes' rule of signs to determine... (answered by venugopalramana)

Question: Find the center and radius of x^2+y^2-6x-2y-6=0 Possible Answers: (A) none (answered by Fermat)