SOLUTION: Please help: 2x^2+3x=20

Question 30144: Please help:
2x^2+3x=20

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
Rewrite the equation as 2x~2+3x-20=0.
The factors of 2 are 1&2, the factors of 20 are 1,2,4,5,10,&20.
Because the number is - one number must be = & the other one -.
The combinations or multiplying 1&2 to each set of factors of 20 must have a difference of 3. The only combination is (1x+5)&(2x-4)or 5-8= -3
Therefore the factors are(x-4)x(2x+5). x times 2x=2x~2
-4 times 2x=-8x
x times 5=5x
-4 times 5=20
2x~2-8x+5x-20=0
2x~2-3x-20=0

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