SOLUTION: The number of bacteria present in a culture after t minutes is given as B = 10e^kt. If there are 7212 bacteria resent after 11 minutes, kind k.
Algebra.Com
Question 29812: The number of bacteria present in a culture after t minutes is given as B = 10e^kt. If there are 7212 bacteria resent after 11 minutes, kind k.
Answer by Fermat(136) (Show Source): You can put this solution on YOUR website!
B = 10e^(kt)
B = 7,212, t = 11
.: 7212 = 10e^(11k)
721.2 = e^(11k)
taking logs of both sides,
ln(721.2) = 11k
11k = 6.5809
k = 0.598265
============
RELATED QUESTIONS
The number of bacteria present in a culture after t minutes is given as B=10e^kt. If... (answered by rapaljer)
The number of bacteria present in a culture after t minutes is given as B=10e^kt. If... (answered by josgarithmetic)
The number of bacteria present in a culture after t minutes is given as B=10e^kt. If... (answered by josgarithmetic,MathTherapy)
The number of bacteria present in a culture after t minutes is given as
B= 100e^kt. IF... (answered by smik)
The number of bacteria present in a culture after t minutes is given as B=1000e^(kt). If... (answered by rapaljer)
the number of bacteria in a culture after t minutes is given as B=1000e^(kt). There are... (answered by stanbon,ewatrrr)
Can you help please.
The question reads: The number of bacteria present in a culture... (answered by mukhopadhyay,Earlsdon)
QUestion: The number of bacteris present in a culture after t minutes is given as... (answered by ikdeep)
Please help w/ the following exponential function:
The number of bacteria present in a... (answered by stanbon)