SOLUTION: 3/(x+1) +4/(x-2)=(px+q)/(x+1)(x-2)
What is the value of p and q?
Algebra.Com
Question 287802: 3/(x+1) +4/(x-2)=(px+q)/(x+1)(x-2)
What is the value of p and q?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
3/(x+1) +4/(x-2)=(px+q)/(x+1)(x-2)
3(x-2)+4(x+1)= (px+q)(x+1)(x-2)/(x+1)(x-2)
3x-6+4x+4 = (px+q)
7x-2 = px+q
q=(7x-2)-px
p=(7x-2)-q /x
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