SOLUTION: Find an equation of the line that contains the given point and is perpendicular to the given line. (-7,-8), x+5y=15 Thank you.

Question 281764: Find an equation of the line that contains the given point and is perpendicular to the given line.
(-7,-8), x+5y=15
Thank you.
Found 2 solutions by subudear, richwmiller:
Answer by subudear(62) (Show Source): You can put this solution on YOUR website!
To find the line perpendicular to any line, just reverse the coefficients of x and y with signs.
so line perpendicular to x + 5y = 15 will be 5x - y = k, we need ot find this k.
As this line passes through (-7,-8) so replace values for x and y in the equation
5x - y = k
5(-7) - (-8) = k
k = -27
so equation of line will be 5x -y = -27
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
slope = -a/b
-1/5
-8=5*-7+b
-8=-35+b
b=27
y=5x+27
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