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write the equation of a line in standard form if m=-3/5 and contains (7, -11)
One standard form of a line is the slope-intercept:
y = m*x + b
In this form m is the slope of the line and b is the value of y when x is zero( that is the value of y where the line crosses the y-axis).
In this case m = -3/5 so we have:
y = (-3/5)*x + b
Since the line passes through the point (7,-11) we know that when x = 7,
y = -11.
So substituting in the equation above we have:
-11 = (-3/5)*7 + b
-11 = -21/5 + b
b = 21/5 - 55/5 = -34/5
The equation of the line then is:
y = (-3/5)*x - 34/5