SOLUTION: 300x+100y+50z=800 20x+5y+5z=55 20y+44z=220

Algebra.Com
Question 264863: 300x+100y+50z=800
20x+5y+5z=55
20y+44z=220

Answer by JBarnum(2146)   (Show Source): You can put this solution on YOUR website!
These are so much fun, Use substitution to solve
divide by 50
divide by 5
divide by 4
Re-write the reduced equations:



------------------------
solve this one for "z"


.
solve for y







.
solve for x







x=9/8 now find "y"
------------------------------





y=11/4 now find "z"
-------------------------------






z=15/4 now to do a check
----------------------------------





that means its correct
this took me a real long time I hope it will be easy to understand.

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