SOLUTION: The power of i. solve for i^25

SOLUTION: The power of i. solve for i^25

Algebra.Com

Question 263605: The power of i.
solve for i^25

Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
The imaginary powers are circular:
i^1= sqrt(-1)
i^2 = -1
i^3 = -i
i^4 = 1
i^5 = i
so,
when you are given a power divide it by 4 and look at the remainder
25/4 = 6 r1
the r1 means that we have
i^1 = i
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