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put this solution on YOUR website!Let the cost for childern diner be x
Let the cost for adult diner be y
x+y=210
y=210-x (subsitution)
3.5x+6y=935
3.5x+6(210-x)=935
3.5x+1260-6x=935
-2.5x = -325
x=130
y=210-130
y=80
Hence, about 80 adults diner were sold, and about 130 childern dinner were sold.
Paul.