You can
put this solution on YOUR website!1. No, sqrt[(-3)^2] is not -3
2. a. x-sqrt(x) =0
x = sqrt (x)
Square both sides to get:
x^2 = x
x^2-x=0
x(x-1)=0
x =0 or x=1
b. That's a good way to solve an equation. Graph the
left side of the equation, i.e. y=x and the right side
y=sqrtx and see where they intersect. The x-value of the
points of intersection will be the potential answers to
the problem. It is possible that a particular answer
will be extraneous so potential answers need to be checked
in the original equation.
Cheers,
Stan H.