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number of dimes = d
number of nickels = n
so
Megan has 7 more dimes than nickels
-->> d = n + 7
Megan has a total of $1.60
-->> (.10)d + (.05)n = $1.60
pluggin 'n+7' in for 'd'
-->> (.10)(n+7) + (.05)n = 1.60
-->> .10n + .70 + .05n = 1.60
-->> .15n + .70 = 1.60
-->> .15n = .90
-->> n = 6
-->> d=n+7=13