SOLUTION: x+3y+2z=1
2z+y-z=2
x+y+z=2
Algebra.Com
Question 245570: x+3y+2z=1
2z+y-z=2
x+y+z=2
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
should the second equation be
2x+y-z=2
repost with correct info
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