SOLUTION: To produce a 16% alcohol solution, a chemist mixes a 20% alcohol solution and a 14% alcohol solution. How much 20% solution and how much 14% solution must be used to product 15 L o

Question 236560: To produce a 16% alcohol solution, a chemist mixes a 20% alcohol solution and a 14% alcohol solution. How much 20% solution and how much 14% solution must be used to product 15 L of a 16% alcohol solution?
Would really appreciate any help. I am studying for an exam tomorrow. Thanks.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.20x+.14(15-x)=.16*15
.20x+2.1-.14x=2.4
.06x=2.4-2.1
.06x=.3
x=.3/.06
x=5 L. of 20% alcohol is used.
15-5=10 L. of 14% alcohol is used.
Proof:
.20*5+.14*10=2.4
1+1.4=2.4
2.4=2.4
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