SOLUTION: log (x2y4/z3)
log8 (x3y4/z5)
log2 (x/y2z3)
logx243=5
Algebra.Com
Question 223239: log (x2y4/z3)
log8 (x3y4/z5)
log2 (x/y2z3)
logx243=5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log (x2y4/z3)
= 2log(x) + 4log(y) - 3log(z)
---------------------------------------
log8 (x3y4/z5)
= 3log8(x) + 4log8(y) - 3log(z)
---------------------------------------
log2 (x/y2z3)
= log2(x) - 2log2(y) - 3log2(z)
---------------------------------------
logx243=5
logx(243) = 5
x^5 = 243
x = 3
======================
Cheers,
Stan H.
RELATED QUESTIONS
log8/log2=x (answered by ikleyn)
log2(x)+log8(x) =... (answered by nerdybill)
log8+log2 (answered by mananth)
Log(5+x)-log(x-2)=log2 (answered by tommyt3rd)
Log(4+x)-log(x-5)=log2 (answered by Theo)
log... (answered by Fombitz)
log2 x -log2 3=log 2(2x-5) (answered by atif.muhammad,tran3209,venugopalramana)
Log (x)+ log (x-2)=log8 (answered by ikleyn)
log8(3x-2)=2
log2(4x)-log2(3=6)
4e^2x+1=12
log6(x+6)+log6(2=2)
log3[log2(x+5)]=1... (answered by stanbon)