SOLUTION: Factoring completely:
5x^8 – 1280 Could the answer be: 5(x^4 + 16)(x^4 -16) ?
___________ ______
2x²(p+q³) – (p + q³) Could the answer be (2-x^2) (p + q^3) ?
___________ __
Algebra.Com
Question 187324: Factoring completely:
5x^8 – 1280 Could the answer be: 5(x^4 + 16)(x^4 -16) ?
__________________
2x²(p+q³) – (p + q³) Could the answer be (2-x^2) (p + q^3) ?
__________________
Simplify: (6+ 1/3)/(4- 2/9) Could the answer be 57 / 17 ?
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Solve the problem:
The perimeter of a rectangle is 62m. If the width were doubled and the length were increased by 21m, the perimeter would be 120m. What are the length and width of the rectangle?
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Solve the equation:
3/y = y/(Sy-12)
__________________
Subtract. Simplify if possible.
(2x+5)/(x²+8x+15) – (x+2)/(x²+8x+15) Could the answer be 1 / x+5 ?
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Factoring completely:
5x^8 – 1280 Could the answer be:
= 5(x^4 + 16)(x^4 -16)
= 5(x^4+16)(x^2+4)(x+2)(x-2)
__________________
2x²(p+q³) – (p + q³)
= (p+q^3)(2x^2-1)
= (p+q^3)(sqrt(2)x -1)(sqrt(2)x + 1)
------------------------------------------
Simplify: (6+ 1/3)/(4- 2/9)
= (19/3) / (34/9)
= (19/3)*(9/34)
= (19)*(3/34)
= 57/34
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Solve the problem:
The perimeter of a rectangle is 62m. If the width were doubled and the length were increased by 21m, the perimeter would be 120m. What are the length and width of the rectangle?
Equations:
L + W = 31
(L+21) + 2W = 60
--------------------------
Rearrange:
L + W = 31
L +2W = 39
----------------
Subtract 1st from 2nd to solve for "w":
W = 8 meters
--
Substitute to solve for "L
L + 8 = 31
L = 23 meters
__________________
Solve the equation:
3/y = y/(Sy-12)
Note: Did you mean to put "S" in the equation?
__________________
Subtract. Simplify if possible.
(2x+5)/(x²+8x+15) – (x+2)/(x²+8x+15)
---
The denominators are the same ; combine the numerators over the denominator:
[2x+5 - (x+2)]/[(x+3)(x+5)]
= [x+3]/[(x+3)(x+5)]
= 1/(x+5)
You are correct.
==========================
Cheers,
Stan H.
___________________
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