SOLUTION: I could really use some help on these problems. I am working on Quadratic Equations and do not get it. They keep giving me problems from a section called SYNTHESIS and it really

Question 185856: I could really use some help on these problems. I am working on Quadratic Equations and do not get it. They keep giving me problems from a section called SYNTHESIS and it really goes beyond what they are teaching me and there is no explanation on how to solve the problem.
ANY HELP WOULD BE GREAT!

x� + √22x = 0

4/(m�-7) = 1

(y + 5) (y � 1) = 27

Solve h = 16t� + vt + s for t.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x� + √22x = 0
Is it x*sqrt(22)? Or sqrt(22x)?
--------------
4/(m�-7) = 1
Multiply by (m^2 - 7)
4 = m^2-7
m^2 = 11
m = +sqrt(11), -sqrt(11)
------------------
(y + 5)(y � 1) = 27
y^2 + 4y - 5 = 27
y^2 + 4y - 32 = 0
(y+8)*(y-4) = 0
y = -8, +4
----------------
Solve h = 16t� + vt + s for t.
16t^2 + vt +(s-h) = 0
t = -v/32 +- sqrt(v^2 - 64(s-h))/32
via quadratic formula
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