SOLUTION: solve each system..(please) and (thanks:) 1. y=2x+8 y=3x-1 2. 2x-y=2 2x-2y=4 3. -x+y=2 2x+y=-1

Question 176605: solve each system..(please) and (thanks:)
1. y=2x+8
y=3x-1
2. 2x-y=2
2x-2y=4
3. -x+y=2
2x+y=-1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1. y=2x+8
y=3x-1
---
Substitute to get:
2x+8 = 3x-1
x = 9
---
Since y = 2x+8, y = 2*9+8 = 26
----------------------------------
2. 2x-y=2
2x-2y=4
solve each for y:
y = 2x-2
y = x-2
Substitute:
2x-2 = x-2
x = 0
--------
Since y = x-2, y = 0-2 = -2
---------------------------------
3. -x+y=2
2x+y=-1
Solve each for Y
y = x + 2
y = -2x-1
Substitute to get:
x+2 = -2x-1
3x = -3
x = -1
Since y = x+2, y = -1+2 = 1
=============================
Cheers,
Stan H.

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