Questions on Algebra: Linear Algebra (NOT Linear Equations) answered by real tutors!

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Question 166922: Approximate to the nearest tenth, the real root of the equation f(x)=x^3-4=0: Approximate to the nearest tenth, the real root of the equation f(x)=x^3-4=0
Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=x^3-4=0
f(x)=x^3=4
x=cubert4
x=1.6 answer.