SOLUTION: Approximate to the nearest tenth, the real root of the equation f(x)=x^3-4=0

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Question 166922: Approximate to the nearest tenth, the real root of the equation f(x)=x^3-4=0
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
f(x)=x^3-4=0
f(x)=x^3=4
x=cubert4
x=1.6 answer.

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