# SOLUTION: State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10x-4. I must show my work. This is from a worksheet and I'm not sure how to

Algebra ->  Algebra  -> College  -> Linear Algebra -> SOLUTION: State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10x-4. I must show my work. This is from a worksheet and I'm not sure how to       Log On

 Algebra: Linear Algebra (NOT Linear Equations) Solvers Lessons Answers archive Quiz In Depth

 Question 166495: State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10x-4. I must show my work. This is from a worksheet and I'm not sure how to do it. ThanksAnswer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10x-4. g(-x) = -9x^2 - 7x^2 - 10x -4 ------------------------------------- Using DesCartes Rule of Signs: # of changes of sign in g(x) = 3; so 1 or 3 positive Real roots ------------------------------ # of changes of sign in g(-x) = 0; so 0 negative Real Roots ------------------------------ # of imaginary zeroes is 0 or two because g(x) is a cubic ================================ Comment: graphing g(x) is find it has one positive Real Root. So it must have 2 imaginary roots. ================================= Cheers, Stan H.