SOLUTION: {{{(x-1)/(2x+1))}}}= {{{(x+1)/(x-1)}}} Enter the smaller number here __ and the larger on here __. Can some one please explain this to me. I don't have any clue as to how they want

Algebra ->  Algebra  -> College  -> Linear Algebra -> SOLUTION: {{{(x-1)/(2x+1))}}}= {{{(x+1)/(x-1)}}} Enter the smaller number here __ and the larger on here __. Can some one please explain this to me. I don't have any clue as to how they want      Log On


   

Question 16273: %28x-1%29%2F%282x%2B1%29%29= %28x%2B1%29%2F%28x-1%29 Enter the smaller number here __ and the larger on here __. Can some one please explain this to me. I don't have any clue as to how they want this solved.
Found 2 solutions by Earlsdon, tjnw79:
Answer by Earlsdon(6287) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
%28x+-+1%29%2F%282x+%2B+1%29+=+%28x+%2B+1%29%2F%28x+-+1%29 Cross-multiply.
%28x+-+1%29%28x+-+1%29+=+%28x+%2B+1%29%282x+%2B+1%29 Perform the indicated multiplication on both sides.
x%5E2+-+2x+%2B+1+=+2x%5E2+%2B+3x+%2B+1 Subtract x^2 from both sides.
-2x+%2B+1+=+x%5E2+%2B+3x+%2B+1 Add 2x to both sides.
1+=+x%5E2+%2B+5x+%2B+1 Subtract 1 from both sides.
0+=+x%5E2+%2B+5x Factor an x on the right side.
0+=+x%28x+%2B+5%29 App;y the zero products principle.
x+=+0 and/or x+%2B+5+=+0
If x+%2B+5+=+0, then x+=+-5
The two roots are:
x = 0
x = -5
Finally:
The smaller number is -5
The larger number is 0

Answer by tjnw79(57) About Me  (Show Source):
You can put this solution on YOUR website!
Thank you I would have never got it.