SOLUTION: x+5y-z=16 3x-3y+2z=12 2x+4y+z=20 Please help me solve this. I have tried and keep getting a decimil point that doesn't fit in.

Algebra.Com
Question 160050: x+5y-z=16
3x-3y+2z=12
2x+4y+z=20
Please help me solve this. I have tried and keep getting a decimil point that doesn't fit in.

Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
add 1st eqn and 3rd eqn __ 3x+9y=36 __ x+3y=12 __ x=12-3y

multiply 1st eqn by 2, then add 2nd eqn __ 5x+7y=44

substituting __ 5(12-3y)+7y=44 __ 60-8y=44 __ y=2

substituting __ x=12-3(2) __ x=6

substituting __ (6)+5(2)-z=16 __ z=0

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