SOLUTION: Ten apples cost a penny, and 25 pears cost two pennies. Suppose I buy 100 apples and pear for 9 1/2 pennies. How may of each shall I have?

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Question 158115This question is from textbook Algebra 2
: Ten apples cost a penny, and 25 pears cost two pennies. Suppose I buy 100 apples and pear for 9 1/2 pennies. How may of each shall I have? This question is from textbook Algebra 2

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
10A=1 OR A=.1
25P=2 OR P=.08
A+P=100 OR A=100-P
.1A+.08P=9.5
.1(100-P)+.08P=9.5
10-.1P+.08P=9.5
-.02P=9.5-10
-.02P=-.5
P=-.5/-.02
P=25 PEARS.
100-25=75 APPLES.
PROOF:
.1*75+.08*25=9.5
7.5+2=9.5
9.5=9.5