SOLUTION: What is the equation of the line that passes through the point (1,5) and has a slope of -3?

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Use the "point slope" form of a line:
http://www.purplemath.com/modules/strtlneq2.htm
.
y – y1 = m(x – x1)
The problem gave you:
a point (1,5) and a slope of -3
.
plug it in and solve:
y – y1 = m(x – x1)
y – 5 = -3(x – 1)
y – 5 = -3x + 3
y = -3x + 8 (this is what they are looking for)