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put this solution on YOUR website!Find a vector x with ||x||=2 that has the same direction as the vector defined by the points A(3,2,1) and B(1,-1,0).
The opposite direction?
direction of ab = i(1-3)+j(-1-2)+k(0-1) = -2i-3j-k
vector x has sime direction .Hence vector|x|= s*(-2i-3j-k) where s is a scalar to be found ||x|| = s*||(-2i-3j-k)||=s*

s*

=s*

= 2...given
Hence s = (2/*

)
vector |x| = (2/*

)*(-2i-3j-k) ....answer
if the direction is opposite then vector |x| = (2/*

)*(2i+3j+k)