SOLUTION: the domain of the function F: x->x^3-5 is D={0,1,2,3,4}. Find the range of f.

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Just plug on the 5 values given for the domain and make a set of the results. That will be the range.
So when x = 0, f(x) = 0^3 - 5 = -5
when x = 1, f(x) = 1^3 - 5 = 1 - 5 = -4
x=2 , f(x) = 2^3 - 5 = 8 - 5 = 3
and so on
range = {-5, -4, 3, add your two other answers here}