Question 150744: what is the equation in the standard form of the line through (4,1) and (-2,3)?
Answer by Electrified_Levi(103)   (Show Source):
You can put this solution on YOUR website! Hi, Hope I can help,
.
what is the equation in the standard form of the line through (4,1) and (-2,3)?
.
First, we need to find the slope of the line.
.
We can find the slope by using the two points ( the slope is equal to  or 
.
We will use the first equation
.
(4,1)( x1 , y1 ) and (-2,3) ( x2 , y2 )
.
.
.
.
It will reduce to 
.
-  is the slope
.
The slope intercept form of a line =  m = slope, b = unknown
.
We can replace "m" with -
.
It becomes 
.
We can find "b" by replacing "x" and "y" with one of our points
.
(4,1)(x,y) and (-2,3) (x,y)
.
We will use the first point, (4,1) (x,y)
.
.
.
.
We will move  to the left
.
.
.
.
We can replace "b" with  in our equation
.
.
.
That is the slope intercept form of the equation, The standard form is 
.
To get it to the standard form, we need to get rid of the fractions
.
.
We will multiply everything by "3"
.
.
.
.
We will move (-x) to the left side
.
.
.
.
is the standard form,
.
.
.
.
We can check by replacing "x" and "y" with the two points
.
(4,1) and (-2,3)
.
We will use the first point, (4,1) (x,y)
.
.
.
.
 True
.
We will use the second point, (-2,3) (x,y)
.
.
.
.
True
.
Some other points to = (1,2), (7,0), and (-8,5)
.
is the standard equation for the line
.
Hope I helped, Levi
|
|
|
