SOLUTION: what is the equation in the standard form of the line through (4,1) and (-2,3)?

Question 150744: what is the equation in the standard form of the line through (4,1) and (-2,3)?
Answer by Electrified_Levi(103) (Show Source): You can put this solution on YOUR website!
Hi, Hope I can help,
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what is the equation in the standard form of the line through (4,1) and (-2,3)?
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First, we need to find the slope of the line.
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We can find the slope by using the two points ( the slope is equal to or
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We will use the first equation
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(4,1)( x1 , y1 ) and (-2,3) ( x2 , y2 )
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It will reduce to
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- is the slope
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The slope intercept form of a line = m = slope, b = unknown
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We can replace "m" with -
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It becomes
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We can find "b" by replacing "x" and "y" with one of our points
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(4,1)(x,y) and (-2,3) (x,y)
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We will use the first point, (4,1) (x,y)
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We will move to the left
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We can replace "b" with in our equation
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That is the slope intercept form of the equation, The standard form is
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To get it to the standard form, we need to get rid of the fractions
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We will multiply everything by "3"
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We will move (-x) to the left side
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is the standard form,
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We can check by replacing "x" and "y" with the two points
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(4,1) and (-2,3)
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We will use the first point, (4,1) (x,y)
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True
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We will use the second point, (-2,3) (x,y)
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True
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Some other points to = (1,2), (7,0), and (-8,5)
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is the standard equation for the line
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Hope I helped, Levi

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