SOLUTION: I have a question on a story problem...
Mary has a total of $4.75 in her bank. There are 39 coins in all: some are dimes are some are quarters. How many coins of each are there in
Algebra ->
College
-> Linear Algebra
-> SOLUTION: I have a question on a story problem...
Mary has a total of $4.75 in her bank. There are 39 coins in all: some are dimes are some are quarters. How many coins of each are there in
Log On
Question 121687: I have a question on a story problem...
Mary has a total of $4.75 in her bank. There are 39 coins in all: some are dimes are some are quarters. How many coins of each are there in her bank?
please
d+q=39
10d+25q=475
You can put this solution on YOUR website! Mary has a total of $4.75 in her bank. There are 39 coins in all: some are dimes are some are quarters. How many coins of each are there in her bank?
please
-------------------
d+q=39
10d+25q=475
------------
d=39-q
Substitute to solve for "q":
10(39-q)+25q=475
390-10q+25q=475
15q = 85
-------------
Comment: q does not become a whole number.
Check your statement of the problem.
------------
Cheers,
Stan H.