SOLUTION: I have a question on a story problem...
Mary has a total of $4.75 in her bank. There are 39 coins in all: some are dimes are some are quarters. How many coins of each are there in
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Question 121687: I have a question on a story problem...
Mary has a total of $4.75 in her bank. There are 39 coins in all: some are dimes are some are quarters. How many coins of each are there in her bank?
please
d+q=39
10d+25q=475
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Mary has a total of $4.75 in her bank. There are 39 coins in all: some are dimes are some are quarters. How many coins of each are there in her bank?
please
-------------------
d+q=39
10d+25q=475
------------
d=39-q
Substitute to solve for "q":
10(39-q)+25q=475
390-10q+25q=475
15q = 85
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Comment: q does not become a whole number.
Check your statement of the problem.
------------
Cheers,
Stan H.
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